We are given the following:
- Cost function: \( C(x) = 20x + 4000 \)<br>
- Revenue function: \( R(x) = 60x + 2000 \)<br>
To find the value of \( x \) (the number of items) that will give a profit, we need to calculate the profit function. The profit function is the difference between revenue and cost:<br>
\[
\text{Profit} = R(x) - C(x)
\]<br>
Substituting the given functions:<br><br>
\[
\text{Profit} = (60x + 2000) - (20x + 4000)
\]<br>
Simplifying:<br>
\[
\text{Profit} = 60x + 2000 - 20x - 4000
\]<br>
\[
\text{Profit} = 40x - 2000
\]<br>
To earn a profit, the profit must be greater than 0:<br><br>
\[
40x - 2000 > 0
\]<br>
Solving for \( x \):<br>
\[
40x > 2000
\]
\[
x > \frac{2000}{40}
\]
\[
x > 50
\]<br>
Therefore, the value of \( x \) to earn a profit is greater than 50.<br>
The correct answer is (A) : >50