
The corresponding logic gate for the given truth table is
Step 1: Understanding the given truth table.
The truth table shows that the output is 1 when either \( A \) or \( B \) is 1, but not both. This corresponds to the behavior of an XOR (exclusive OR) gate, which outputs 1 when exactly one of the inputs is 1, and 0 when both inputs are the same.
Step 2: Identifying the logic gate.
XOR gate outputs 1 when the inputs are different, and 0 when they are the same.
OR gate outputs 1 if either of the inputs is 1.
AND gate outputs 1 only when both inputs are 1.
NAND gate is the inverse of the AND gate, outputting 1 except when both inputs are 1.
Thus, the correct answer is
(A) XOR.
For the gate shown in the figure, the output will be HIGH

The following circuit generates the same output as?

At 15 atm pressure, $ \text{NH}_3(g) $ is being heated in a closed container from 27°C to 347°C and as a result, it partially dissociates following the equation: $ 2\text{NH}_3(g) \rightleftharpoons \text{N}_2(g) + 3\text{H}_2(g) $ If the volume of the container remains constant and pressure increases to 50 atm, then calculate the percentage dissociation of $ \text{NH}_3(g) $
If equilibrium constant for the equation $ A_2 + B_2 \rightleftharpoons 2AB \quad \text{is} \, K_p, $ then find the equilibrium constant for the equation $ AB \rightleftharpoons \frac{1}{2} A_2 + \frac{1}{2} B_2. $
Consider the following reaction: $ \text{CO}(g) + \frac{1}{2} \text{O}_2(g) \rightarrow \text{CO}_2(g) $ At 27°C, the standard entropy change of the process becomes -0.094 kJ/mol·K. Moreover, standard free energies for the formation of $ \text{CO}_2(g) $ and $ \text{CO}(g) $ are -394.4 and -137.2 kJ/mol, respectively. Predict the nature of the above chemical reaction.