The correct statement about the following disaccharide is
- Ring $(i)$ is pyranose with $\alpha$-glycosidic link
- Ring $(i)$ is furanose with $\alpha$-glycosidic link
- Ring $(ii)$ is furanose with $\alpha$-glycosidic link
- Ring $(ii)$ is pyranose with $\beta$-glycosidic link
The Correct Option is A
Solution and Explanation
(a) is a pyranose and it has ether linkage at $\alpha$-position that is known as $\alpha$-glycosidic linkage in carbohydrate chemistry
Top Questions on Carbohydrates
- Match List - I with List - II. \[ {List - I (Saccharides)} \quad {List - II (Glycosidic-linkages found)} \] \[ {(A) Sucrose} \quad {(I) } \alpha 1-4 \] \[ {(B) Maltose} \quad {(II) } \alpha 1-4 { and } \alpha 1-6 \] \[ {(C) Lactose} \quad {(III) } \alpha 1-\beta 2 \] \[ {(D) Amylopectin} \quad {(IV) } \beta 1-4 \] Choose the correct answer from the options given below:
- JEE Main - 2025
- Chemistry
- Carbohydrates
The carbohydrates “Ribose” present in DNA is
A. A pentose sugar
B. Present in pyranose form
C. In “D” configuration
D. A reducing sugar, when free
E. In \( \alpha \)-anomeric form- JEE Main - 2025
- Chemistry
- Carbohydrates
- Given below are two statements:
Statement I: Fructose does not contain an aldehydic group but still reduces Tollen’s reagent.
Statement II: In the presence of base, fructose undergoes rearrangement to give glucose.
In the light of the above statements, choose the correct answer from the options given below.- JEE Main - 2025
- Chemistry
- Carbohydrates
Match List - I with List - II:
List - I:
(A) Amylase
(B) Cellulose
(C) Glycogen
(D) Amylopectin
List - II:
(I) β-C1-C4 plant
(II) α-C1-C4 animal
(III) α-C1-C4 α-C1-C6 plant
(IV) α-C1-C4 plant
- JEE Main - 2025
- Chemistry
- Carbohydrates
- Identify the difference between the sugars in DNA and RNA.
- CUET (PG) - 2025
- Home Science
- Carbohydrates
Questions Asked in JEE Advanced exam
The center of a disk of radius $ r $ and mass $ m $ is attached to a spring of spring constant $ k $, inside a ring of radius $ R>r $ as shown in the figure. The other end of the spring is attached on the periphery of the ring. Both the ring and the disk are in the same vertical plane. The disk can only roll along the inside periphery of the ring, without slipping. The spring can only be stretched or compressed along the periphery of the ring, following Hooke’s law. In equilibrium, the disk is at the bottom of the ring. Assuming small displacement of the disc, the time period of oscillation of center of mass of the disk is written as $ T = \frac{2\pi}{\omega} $. The correct expression for $ \omega $ is ( $ g $ is the acceleration due to gravity):
- JEE Advanced - 2025
- Waves and Oscillations
- Consider the vectors $$ \vec{x} = \hat{i} + 2\hat{j} + 3\hat{k},\quad \vec{y} = 2\hat{i} + 3\hat{j} + \hat{k},\quad \vec{z} = 3\hat{i} + \hat{j} + 2\hat{k}. $$ For two distinct positive real numbers $ \alpha $ and $ \beta $, define $$ \vec{X} = \alpha \vec{x} + \beta \vec{y} - \vec{z},\quad \vec{Y} = \alpha \vec{y} + \beta \vec{z} - \vec{x},\quad \vec{Z} = \alpha \vec{z} + \beta \vec{x} - \vec{y}. $$ If the vectors $ \vec{X}, \vec{Y}, \vec{Z} $ lie in a plane, then the value of $ \alpha + \beta - 3 $ is ________.
- If $$ \alpha = \int_{\frac{1}{2}}^{2} \frac{\tan^{-1} x}{2x^2 - 3x + 2} \, dx, $$ then the value of $ \sqrt{7} \tan \left( \frac{2\alpha \sqrt{7}}{\pi} \right) $ is.
(Here, the inverse trigonometric function $ \tan^{-1} x $ assumes values in $ \left( -\frac{\pi}{2}, \frac{\pi}{2} \right) $.)- JEE Advanced - 2025
- Integral Calculus
Let $ a_0, a_1, ..., a_{23} $ be real numbers such that $$ \left(1 + \frac{2}{5}x \right)^{23} = \sum_{i=0}^{23} a_i x^i $$ for every real number $ x $. Let $ a_r $ be the largest among the numbers $ a_j $ for $ 0 \leq j \leq 23 $. Then the value of $ r $ is ________.
- JEE Advanced - 2025
- binomial expansion formula
- The total number of real solutions of the equation $$ \theta = \tan^{-1}(2 \tan \theta) - \frac{1}{2} \sin^{-1} \left( \frac{6 \tan \theta}{9 + \tan^2 \theta} \right) $$ is
(Here, the inverse trigonometric functions $ \sin^{-1} x $ and $ \tan^{-1} x $ assume values in $[-\frac{\pi}{2}, \frac{\pi}{2}]$ and $(-\frac{\pi}{2}, \frac{\pi}{2})$, respectively.)- JEE Advanced - 2025
- Inverse Trigonometric Functions
Concepts Used:
Carbohydrates
Carbohydrates, or carbs, are sugar molecules. Along with proteins and fats, carbohydrates are one of three main nutrients found in foods and drinks.
Your body breaks down carbohydrates into glucose. Glucose, or blood sugar, is the main source of energy for your body's cells, tissues, and organs. Glucose can be used immediately or stored in the liver and muscles for later use.
Classification of Carbohydrates
Carbohydrates are divided into two categories: simple and complex, based on their chemical structure and degree of polymerization.
Simple Carbohydrates (Monosaccharides, Disaccharides and Oligosaccharides)
One or two sugar molecules make up simple carbohydrates. Simple carbohydrates cause blood sugar levels to rise because molecules are easily digested and converted. Milk products, alcohol, vegetables, processed sugars, candies, and other foods contain a lot of them. These carbohydrates are referred to as "empty calories" because they lack fibre, vitamins, and minerals.
Complex Carbohydrates (Polysaccharides)
Starchy foods contain two or more sugar molecules and are thus referred to as complex carbohydrates. In comparison to simple carbohydrates, molecules in complex carbohydrates are digested and converted slowly. They are found in large quantities in potatoes, corn, cereals, lentils, peanuts, beans, whole-grain bread, peas, etc.
Carbohydrates can be found in the following examples:
- Glucose
- Galactose
- Maltose
- Fructose
- Sucrose
- Lactose
- Starch
- Cellulose
- Chitin