Question

Statement-I: Sucrose is dextrorotatory and upon hydrolysis, it becomes laevorotatory. Statement-II: Sucrose on hydrolysis gives glucose and fructose such that the laevorotation of glucose is more than dextrorotation of fructose. Which of the following is correct?

• A. Both Statement-I and Statement-II are correct
• B. Both Statement-I and Statement-II are incorrect
• C. Statement-I is correct, Statement-II is incorrect
• D. Statement-II is correct, Statement-I is incorrect

Hint:

When dealing with optical rotation, remember that the net rotation is the sum of the individual rotations of the components.

Answer 1

The Correct Option is C

Step 1: Statement-I analysis.
Sucrose is indeed dextrorotatory, meaning it rotates plane-polarized light to the right. Upon hydrolysis, it becomes laevorotatory due to the presence of glucose and fructose, which individually rotate light in the opposite direction. Step 2: Statement-II analysis.
Statement-II is not correct. While glucose is laevorotatory and fructose is dextrorotatory, the overall effect of hydrolysis on sucrose is a net change in the direction of rotation, not that the laevorotation of glucose is greater than the dextrorotation of fructose. Step 3: Conclusion.
Thus, Statement-I is correct and Statement-II is incorrect. Final Answer: \[ \boxed{\text{Statement-I is correct, Statement-II is incorrect}} \]