The correct sequence of reactions involved in the following conversion is:
Step 1: Understanding the Reaction Sequence - The given reaction involves conversion of a substituted benzene with nitro (-NO\(_2\)) and methyl (-CH\(_3\)) groups to a brominated product.
Step 2: Identifying the Steps 1. Bromination:
- The presence of a methyl (-CH\(_3\)) group directs bromine to the para position via electrophilic substitution. 2. Reduction of Nitro Group:
- The -NO\(_2\) group is reduced to an amine (-NH\(_2\)) using reducing agents like Sn/HCl. 3. Carbylamine Reaction:
- The -NH\(_2\) group undergoes carbylamine reaction (using CHCl\(_3\) and KOH) to form an isocyanide (-NC).
Step 3: Conclusion
- Since this follows the sequence Bromination → Reduction → Carbylamine Reaction, the correct answer is option (1).
Identify the suitable reagent for the following conversion: $Ph-C(=O)-OCH_3$ $\longrightarrow$ $Ph-CHO$
Why is chlorobenzene resistant to nucleophilic substitution reactions?