To determine the correct IUPAC nomenclature, follow these steps:
Step 1: Identify the parent chain The parent chain consists of 7 carbon atoms (hept-) with a double bond at the 6th carbon (hept-6-en-).
Step 2: Functional groups and priority The compound contains the following functional groups: 1. A formyl group (−CHO) at the 2nd carbon, 2. A hydroxyl group (−OH) at the 4th carbon, 3. A carboxylic acid group (−COOH) at the end of the chain. The carboxylic acid group has the highest priority, so the chain is named as a derivative of ”hept-6-enoic acid”.
Step 3: Naming the substituents 1. The −CHO group is named as ”formyl” since it is a substituent and not the main functional group. 2. The −OH group is named as ”hydroxy”.
Step 4: Combine the name The substituents and parent chain are combined in the order
of their positions:
2-formyl-4-hydroxyhept-6-enoic acid.
Step 5: Validate the given options From the options provided, the correct name matches:
(3) 2-formyl-4-hydroxyhept-6-enoic acid.
Final Answer: (3)
The IUPAC name of the following compound is:
Let \( S = \left\{ m \in \mathbb{Z} : A^m + A^m = 3I - A^{-6} \right\} \), where
\[ A = \begin{bmatrix} 2 & -1 \\ 1 & 0 \end{bmatrix} \]Then \( n(S) \) is equal to ______.
Let \( T_r \) be the \( r^{\text{th}} \) term of an A.P. If for some \( m \), \( T_m = \dfrac{1}{25} \), \( T_{25} = \dfrac{1}{20} \), and \( \displaystyle\sum_{r=1}^{25} T_r = 13 \), then \( 5m \displaystyle\sum_{r=m}^{2m} T_r \) is equal to: