
To determine the correct IUPAC nomenclature, follow these steps:
Step 1: Identify the parent chain The parent chain consists of 7 carbon atoms (hept-) with a double bond at the 6th carbon (hept-6-en-).
Step 2: Functional groups and priority The compound contains the following functional groups: 1. A formyl group (−CHO) at the 2nd carbon, 2. A hydroxyl group (−OH) at the 4th carbon, 3. A carboxylic acid group (−COOH) at the end of the chain. The carboxylic acid group has the highest priority, so the chain is named as a derivative of ”hept-6-enoic acid”.
Step 3: Naming the substituents 1. The −CHO group is named as ”formyl” since it is a substituent and not the main functional group. 2. The −OH group is named as ”hydroxy”.
Step 4: Combine the name The substituents and parent chain are combined in the order
of their positions:
2-formyl-4-hydroxyhept-6-enoic acid.
Step 5: Validate the given options From the options provided, the correct name matches:
(3) 2-formyl-4-hydroxyhept-6-enoic acid.
Final Answer: (3)
Which of the following is the correct IUPAC name of the given organic compound (X)?
The structure of compound $ X $ is as follows:
$ \text{H}_3\text{C} - \text{CH}_3 - \text{CH} = \text{CH} - \text{H} - \text{Br} $
The IUPAC name of the following compound is:

The correct IUPAC name of the compound is: 
Match List - I with List - II: 
Choose the correct answer from the given below options
Let \( ABC \) be a triangle. Consider four points \( p_1, p_2, p_3, p_4 \) on the side \( AB \), five points \( p_5, p_6, p_7, p_8, p_9 \) on the side \( BC \), and four points \( p_{10}, p_{11}, p_{12}, p_{13} \) on the side \( AC \). None of these points is a vertex of the triangle \( ABC \). Then the total number of pentagons that can be formed by taking all the vertices from the points \( p_1, p_2, \ldots, p_{13} \) is ___________.
Consider the following two reactions A and B: 
The numerical value of [molar mass of $x$ + molar mass of $y$] is ___.
Consider an A.P. $a_1,a_2,\ldots,a_n$; $a_1>0$. If $a_2-a_1=-\dfrac{3}{4}$, $a_n=\dfrac{1}{4}a_1$, and \[ \sum_{i=1}^{n} a_i=\frac{525}{2}, \] then $\sum_{i=1}^{17} a_i$ is equal to