To determine the correct IUPAC nomenclature, follow these steps:
Step 1: Identify the parent chain The parent chain consists of 7 carbon atoms (hept-) with a double bond at the 6th carbon (hept-6-en-).
Step 2: Functional groups and priority The compound contains the following functional groups: 1. A formyl group (−CHO) at the 2nd carbon, 2. A hydroxyl group (−OH) at the 4th carbon, 3. A carboxylic acid group (−COOH) at the end of the chain. The carboxylic acid group has the highest priority, so the chain is named as a derivative of ”hept-6-enoic acid”.
Step 3: Naming the substituents 1. The −CHO group is named as ”formyl” since it is a substituent and not the main functional group. 2. The −OH group is named as ”hydroxy”.
Step 4: Combine the name The substituents and parent chain are combined in the order
of their positions:
2-formyl-4-hydroxyhept-6-enoic acid.
Step 5: Validate the given options From the options provided, the correct name matches:
(3) 2-formyl-4-hydroxyhept-6-enoic acid.
Final Answer: (3)
Write IUPAC names of the following compounds:
Let $ f(x) = \begin{cases} (1+ax)^{1/x} & , x<0 \\1+b & , x = 0 \\\frac{(x+4)^{1/2} - 2}{(x+c)^{1/3} - 2} & , x>0 \end{cases} $ be continuous at x = 0. Then $ e^a bc $ is equal to
Total number of nucleophiles from the following is: \(\text{NH}_3, PhSH, (H_3C_2S)_2, H_2C = CH_2, OH−, H_3O+, (CH_3)_2CO, NCH_3\)