To solve the problem, we need to determine the correct IUPAC name of the complex [Pt(NH3)2Cl2]$^{2+}$.
1. Identifying the Central Metal Ion:
The central metal ion in the complex is platinum (Pt), which has a charge of +2, as indicated by the overall charge of the complex being +2.
2. Identifying the Ligands:
The ligands present in the complex are ammonia (NH3) and chloride (Cl-). Ammonia is a neutral ligand, and chloride is a monodentate anionic ligand.
3. Naming the Ligands:
The ligand ammonia is named "ammine," and chloride is named "chloro." There are two of each ligand in the complex.
4. Determining the Oxidation State of Platinum:
To determine the oxidation state of platinum, we assign oxidation states to the ligands. Ammonia is neutral, and chloride has a charge of -1. Let the oxidation state of platinum be x. The total charge of the complex is +2, so we have the equation:
x + 2(-1) = +2
Solving for x: x - 2 = +2, so x = +4.
5. Writing the Full Name:
According to the IUPAC nomenclature, the complex is named by first naming the ligands in alphabetical order, followed by the central metal ion with its oxidation state in parentheses.
Final Answer:
The correct IUPAC name of [Pt(NH3)2Cl2]$^{2+}$ is "diamminedichloroplatinum(IV) ion."
The Crystal Field Theory (CFT) of coordination compounds is based on the effect of different crystal fields (provided by the ligands taken as point charges) on the degeneracy of d-orbital energies of the central metal atom/ion. The splitting of the d-orbitals provides different electronic arrangements in strong and weak crystal fields. In tetrahedral coordination entity formation, the d-orbital splitting is smaller as compared to the octahedral entity.
What is crystal field splitting energy?
The Crystal Field Theory (CFT) of coordination compounds is based on the effect of different crystal fields (provided by the ligands taken as point charges) on the degeneracy of d-orbital energies of the central metal atom/ion. The splitting of the d-orbitals provides different electronic arrangements in strong and weak crystal fields. In tetrahedral coordination entity formation, the d-orbital splitting is smaller as compared to the octahedral entity.
On the basis of CFT, explain why [Ti(H$_2$O)$_6$]Cl$_3$ complex is coloured? What happens on heating the complex [Ti(H$_2$O)$_6$]Cl$_3$? Give reason.