The correct increasing order of number of lone pair of electrons on the central atom of \(SnCl_2\), \(XeF_2\),\( CIF_3\) and \( SO_3\) is
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- \( SO_3\) <\( CIF_3\)<\(SnCl_2\)<\(XeF_2\)
- \( SO_3\)<\(SnCl_2\) <\( CIF_3\)<\(XeF_2\)
- \(XeF_2\)<\(SnCl_2\) <\( CIF_3\)<\( SO_3\)
- \(XeF_2\) <\( CIF_3\)<\(SnCl_2\)<\( SO_3\)
The Correct Option is B
Solution and Explanation
Step 1: \( SO_3\) has no lone pairs on the central atom. \(SnCl_2\) has two lone pairs,\( CIF_3\) has one lone pair, and \(XeF_2\) has three lone pairs.
Step 2: Therefore, the correct increasing order of lone pairs is \( SO_3\)<(SnCl_2\) <\( CIF_3\)<(XeF_2\).
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