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Step 1: Understand the Chemical Formula of Borax Borax has the formula Na\(_2\)[B\(_4\)O\(_5\)(OH)\(_x\)]·yH\(_2\)O, where: - Na\(_2\) is sodium, - B\(_4\)O\(_5\) represents boron and oxygen components, - (OH)\(_x\) is the hydroxide group, - yH\(_2\)O represents water of crystallization. The chemical formula of borax in its most common form is Na\(_2\)B\(_4\)O\(_7\)(OH)\(_4\)·8H\(_2\)O.
Step 2: Determine \(x\) and \(y\) From the formula Na\(_2\)B\(_4\)O\(_7\)(OH)\(_4\)·8H\(_2\)O: - \(x\) represents the number of hydroxide ions (OH), and there are 4 hydroxide ions, so \(x = 4\). - \(y\) represents the number of water molecules of crystallization, and there are 8 water molecules, so \(y = 8\).
Step 3: Calculate the sum of \(x\) and \(y\) Now, sum \(x\) and \(y\): \[ x + y = 4 + 8 = 12 \] Thus, the sum of \(x\) and \(y\) is 12.
The organic halide, which does not undergo hydrolysis by SN1 mechanism is:
Option 1: C6H5CH2Cl
Option 2: CH2CH - CH2Cl
Option 3: (CH3)3C - Cl
Option 4: CH3 - CH = CH - Cl
A constant force of \[ \mathbf{F} = (8\hat{i} - 2\hat{j} + 6\hat{k}) \text{ N} \] acts on a body of mass 2 kg, displacing it from \[ \mathbf{r_1} = (2\hat{i} + 3\hat{j} - 4\hat{k}) \text{ m to } \mathbf{r_2} = (4\hat{i} - 3\hat{j} + 6\hat{k}) \text{ m}. \] The work done in the process is:
A ball 'A' of mass 1.2 kg moving with a velocity of 8.4 m/s makes a one-dimensional elastic collision with a ball 'B' of mass 3.6 kg at rest. The percentage of kinetic energy transferred by ball 'A' to ball 'B' is:
A metre scale is balanced on a knife edge at its centre. When two coins, each of mass 9 g, are kept one above the other at the 10 cm mark, the scale is found to be balanced at 35 cm. The mass of the metre scale is:
A body of mass \( m \) and radius \( r \) rolling horizontally with velocity \( V \), rolls up an inclined plane to a vertical height \( \frac{V^2}{g} \). The body is: