
A manufacturer makes two types of toys A and B. Three machines are needed for production with the following time constraints (in minutes): \[ \begin{array}{|c|c|c|} \hline \text{Machine} & \text{Toy A} & \text{Toy B} \\ \hline M1 & 12 & 6 \\ M2 & 18 & 0 \\ M3 & 6 & 9 \\ \hline \end{array} \] Each machine is available for 6 hours = 360 minutes. Profit on A = Rupee 20, on B = Rupee 30.
Formulate and solve the LPP graphically.
Find the Derivative \( \frac{dy}{dx} \)
Given:\[ y = \cos(x^2) + \cos(2x) + \cos^2(x^2) + \cos(x^x) \]
Solve the following LPP graphically: Maximize: \[ Z = 2x + 3y \] Subject to: \[ \begin{aligned} x + 4y &\leq 8 \quad \text{(1)} \\ 2x + 3y &\leq 12 \quad \text{(2)} \\ 3x + y &\leq 9 \quad \text{(3)} \\ x &\geq 0,\quad y \geq 0 \quad \text{(non-negativity constraints)} \end{aligned} \]