To determine the coordination environment of the \( \text{Ca}^{2+} \) ion in its complex with \( \text{EDTA}^{4-} \), we need to understand how \( \text{EDTA}^{4-} \) acts as a ligand and coordinates with metal ions.
Step 1: Understanding EDTA as a ligand.
Step 2: Coordination Geometry of \( \text{Ca}^{2+} \) with EDTA.
Step 3: Conclusion and Verification.
Thus, the correct answer is that the coordination environment of \( \text{Ca}^{2+} \) ion in its complex with \( \text{EDTA}^{4-} \) is octahedral.
To determine the coordination environment of the \( \text{Ca}^{2+} \) ion in its complex with \( \text{EDTA}^{4-} \), we need to understand the structure and binding nature of \( \text{EDTA}^{4-} \).
\( \text{EDTA}^{4-} \) (ethylenediaminetetraacetic acid) is a hexadentate ligand, which means it can form six bonds with a metal ion. It does this by using its four carboxylate groups and two amine groups. This ability to form six coordinate bonds with a metal ion typically leads to an octahedral geometry.
Let's evaluate each option:
Based on the above analysis, the correct choice is \(octahedral\) because \( \text{EDTA}^{4-} \) provides six coordination sites equating to an octahedral coordination environment.
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