1. For the complex ion [Fe(C\(_2\)O\(_4\))\(_3\)]\(^3-\):
The oxalate ion (C\(_2\)O\(_4\)) is a bidentate ligand, meaning it forms two bonds with the central metal ion.
Since there are 3 oxalate ions in the complex, each forming two bonds with Fe, the total coordination number of Fe is \( 3 \times 2 = 6 \).
2. For the complex ion [Co(SCN)\(_4\)]\(^2-\):
The thiocyanate ion (SCN\(^-\)) is a monodentate ligand, meaning it forms only one bond with the central metal ion.
Since there are 4 SCN\(^-\) ions in the complex, the coordination number of Co is 4.
Thus, the coordination numbers are: Fe: 6, Co: 4
The correct option is (A): 6 and 4
(b.)Calculate the potential for half-cell containing 0.01 M K\(_2\)Cr\(_2\)O\(_7\)(aq), 0.01 M Cr\(^{3+}\)(aq), and 1.0 x 10\(^{-4}\) M H\(^+\)(aq).