>
Exams
>
Mathematics
>
Algebra
>
the boolean expression neg p vee q vee neg p wedge
Question:
The Boolean expression:
\[ \neg (p \vee q) \vee (\neg p \wedge q) \]
is equivalent to:
Show Hint
Using De Morgan's law and distribution simplifies complex Boolean expressions.
BITSAT - 2024
BITSAT
Updated On:
Mar 26, 2025
\( p \)
\( q \)
\( \neg q \)
\( \neg p \)
Hide Solution
Verified By Collegedunia
The Correct Option is
D
Solution and Explanation
Applying De Morgan's Law: \[ \neg (p \vee q) = \neg p \wedge \neg q \] Thus: \[ (\neg p \wedge \neg q) \vee (\neg p \wedge q) \] Using distributive law: \[ \neg p \wedge (\neg q \vee q) \] Since \( \neg q \vee q = 1 \) (tautology): \[ \neg p \wedge 1 = \neg p \] Thus, the Boolean expression simplifies to: \[ \neg p \]
Download Solution in PDF
Was this answer helpful?
0
0
Top Questions on Algebra
Roots of the equation \( x^2 + bx - c = 0 \) (\( b, c>0 \)) are:
BITSAT - 2024
Mathematics
Algebra
View Solution
If the number of available constraints is 3 and the number of parameters to be optimised is 4, then
BITSAT - 2024
Mathematics
Algebra
View Solution
If \( \vec{a} = 2\hat{i} + \hat{j} + 2\hat{k} \), then the value of \( |\hat{i} \times (\vec{a} \times \hat{i})| + |\hat{j} \times (\vec{a} \times \hat{j})| + |\hat{k} \times (\vec{a} \times \hat{k})|^2 \) is equal to:}
BITSAT - 2024
Mathematics
Algebra
View Solution
If the arithmetic mean of two distinct positive real numbers \(a\) and \(b\) (where \(a>b\)) is twice their geometric mean, then \(a : b\) is:
BITSAT - 2024
Mathematics
Algebra
View Solution
The coefficient of \(x^2\) term in the binomial expansion of \(\left(\frac{1}{3}x^{\frac{1}{3}} + x^{-\frac{1}{4}}\right)^{10}\) is:
BITSAT - 2024
Mathematics
Algebra
View Solution
View More Questions
Questions Asked in BITSAT exam
Let \( ABC \) be a triangle and \( \vec{a}, \vec{b}, \vec{c} \) be the position vectors of \( A, B, C \) respectively. Let \( D \) divide \( BC \) in the ratio \( 3:1 \) internally and \( E \) divide \( AD \) in the ratio \( 4:1 \) internally. Let \( BE \) meet \( AC \) in \( F \). If \( E \) divides \( BF \) in the ratio \( 3:2 \) internally then the position vector of \( F \) is:
BITSAT - 2024
Vectors
View Solution
Let \( \mathbf{a} = \hat{i} - \hat{k}, \mathbf{b} = x\hat{i} + \hat{j} + (1 - x)\hat{k}, \mathbf{c} = y\hat{i} + x\hat{j} + (1 + x - y)\hat{k} \). Then, \( [\mathbf{a} \, \mathbf{b} \, \mathbf{c}] \) depends on:}
BITSAT - 2024
Vectors
View Solution
Let the foot of perpendicular from a point \( P(1,2,-1) \) to the straight line \( L : \frac{x}{1} = \frac{y}{0} = \frac{z}{-1} \) be \( N \). Let a line be drawn from \( P \) parallel to the plane \( x + y + 2z = 0 \) which meets \( L \) at point \( Q \). If \( \alpha \) is the acute angle between the lines \( PN \) and \( PQ \), then \( \cos \alpha \) is equal to:
BITSAT - 2024
Plane
View Solution
The magnitude of projection of the line joining \( (3,4,5) \) and \( (4,6,3) \) on the line joining \( (-1,2,4) \) and \( (1,0,5) \) is:
BITSAT - 2024
Vectors
View Solution
The angle between the lines whose direction cosines are given by the equations \( 3l + m + 5n = 0 \) and \( 6m - 2n + 5l = 0 \) is:
BITSAT - 2024
Vectors
View Solution
View More Questions