Question

The bond length of CO is 113 pm and its dipole moment (𝜇⃗) is 0.1 D. The charge (in units of electronic charge) on carbon in the CO molecule including its sign is (rounded off to three decimal places)
[Given: charge of electron = 1.602×10⁻¹⁹ C; 1 D=3.336 × 10⁻³⁰ Cm]

Answer 1

Correct Answer: -0.017 - -0.019

The dipole moment µ is related to the charge q and bond length r by the equation:

\(\mu = q \times r \)

where:

• µ is the dipole moment in Debye (D),
• q is the charge in Coulombs (C),
• r is the bond length in meters (m).

First, convert the bond length from pm (picometers) to meters:

\( r = 113 \text{ pm} = 113 \times 10^{-12} \text{ m} \)

Now, rearrange the equation to solve for q:

\( q = \frac{\mu}{r} \)

Substitute the given values:

\( q = \frac{0.1 \text{ D} \times 3.336 \times 10^{-30} \text{ C m/D}}{113 \times 10^{-12} \text{ m}} \)

Calculating this gives:

\( q \approx -0.019 \text{ C} \)

Thus, the charge on carbon in CO is -0.019 electronic charges.