To determine the average weight of Abhi, Banu, Chaitu, and Deeru using the given statements, let's analyze the problem step by step:
Given Data:
Statement 1: Average weight of Abhi, Banu, and Chaitu is 45 kg.
Let the weights of Abhi, Banu, and Chaitu be \( A \), \( B \), and \( C \) respectively. Then the average weight can be represented as:
\(\frac{A + B + C}{3} = 45\)
Thus, the total weight of Abhi, Banu, and Chaitu is:
\(A + B + C = 135\)
Statement 2: Average weight of Banu, Chaitu, and Deeru is 40 kg.
Let the weight of Deeru be \( D \). Then the average weight can be represented as:
\(\frac{B + C + D}{3} = 40\)
Thus, the total weight of Banu, Chaitu, and Deeru is:
\(B + C + D = 120\)
We also know from the given data that:
This implies:
\(A + D = 80\)
Using Statements Together:
We have the following equations:
We can find the value of \( A + B + C + D \) by combining these equations:
Adding equation (1) and equation (2):
\(A + B + C + B + C + D = 135 + 120\)
\(A + 2B + 2C + D = 255\)
Subtracting equation (3) from the combined equation:
\(A + 2B + 2C + D - (A + D) = 255 - 80\)
\(2B + 2C = 175\)
\(B + C = 87.5\)
Substituting \( B + C \) into equation (1):
\(A + 87.5 = 135\)
\(A = 47.5\)
Substituting \( A \) into equation (3):
\(47.5 + D = 80\)
\(D = 32.5\)
Now, we can find the average weight of Abhi, Banu, Chaitu, and Deeru:
\(A + B + C + D = 47.5 + 87.5 + 32.5\)
\(= 167.5\)
The average weight is:
\(\frac{167.5}{4} = 41.875\text{ kg}\)
Conclusion: Both statements are required to find the average weight of all four people. Thus, the correct answer is: both the statements together are needed to answer the question.
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