Question:

The average of 4 distinct prime numbers a, b, c, d is 35, where a<b<c<d. a and d are equidistant from 36 and b and c are equidistant from 34 and a, b are equidistant from 30 and c and d are equidistant from 40. The difference between a and d is:

Updated On: Oct 4, 2024
  • 30
  • 14
  • 21
  • Cannot be determined
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The Correct Option is B

Solution and Explanation

The correct option is (B): 14
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