The average marks of the three students L, M and N is 80. Another man P enters the group of these three and makes the average 75. Now, a man Q whose marks 6 more than P, replaces M and average of the L, N, P and Q becomes 70. What is the marks of M?
The correct option is (C): 86. L + M + N = 80*3 ___(i) L + M + N + P = 75*4 ___(ii) Solving (i) and (ii), we get 80*3 + P = 75*4 P = 300 - 240 = 60 Q = 6 + P = 66 L + N + P + Q = 70*4 ___(iii) Putting the value of P and Q, we get L + N + 60 + 66 = 280 L + N = 280 - 126 = 154 Now, putting the value of L and N in equation (i), we get 154 + M = 80*3 M = 240 - 154 = 86.