Question:
The area of the curved surface
\(S = \left\{ (x, y, z) ∈ \R^3 : z^2 = (x − 1)^2 + (y − 2)^2 \right\}\)
lying between the planes z = 2 and z = 3 is
The area of the curved surface
\(S = \left\{ (x, y, z) ∈ \R^3 : z^2 = (x − 1)^2 + (y − 2)^2 \right\}\)
lying between the planes z = 2 and z = 3 is
\(S = \left\{ (x, y, z) ∈ \R^3 : z^2 = (x − 1)^2 + (y − 2)^2 \right\}\)
lying between the planes z = 2 and z = 3 is
Updated On: Apr 28, 2025
- \(4\pi\sqrt2\)
- \(5\pi\sqrt2\)
- \(9\pi\)
- \(9\pi\sqrt2\)
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The Correct Option is B
Solution and Explanation
The correct option is (B) : \(5\pi\sqrt2\).
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