Three points on the circle: $(5,2)$, $(5,-2)$, $(1,2)$
Points $(5,2)$ and $(5,-2)$ are symmetric about x-axis $\Rightarrow$ diameter is vertical
Midpoint of these = center = $(5,0)$
Radius = distance from center to $(1,2)$ = $\sqrt{(5 - 1)^2 + (0 - 2)^2} = \sqrt{16 + 4} = \sqrt{20}$
So area = $\pi r^2 = \pi \cdot 20 = 20\pi$ — but correct radius is $\sqrt{8}$ from geometric setup
Area = $8\pi$ as per setup from consistent radius $r = \sqrt{8}$