Question:
The area enclosed between the parabolas y2 = 16x and x2 = 16y is
The area enclosed between the parabolas y2 = 16x and x2 = 16y is
Updated On: Sep 15, 2024
- \(\frac{64}{3}\) sq.units
- \(\frac{256}{3}\) sq.units
- \(\frac{16}{3}\) sq.units
- None of these
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The Correct Option is B
Solution and Explanation
The correct option is (B) : \(\frac{256}{3}\) sq.units.
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