Question:

The area bounded by $y =x^{2} +3$ and $y =2x+3$ is

Updated On: Jun 7, 2024
  • $\frac{12}{7}$
  • $\frac{4}{3}$
  • $\frac{3}{4}$
  • $\frac{8}{3}$
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The Correct Option is B

Solution and Explanation

Required area
$=\int_{0}^{2}(2 x+3)-\left(x^{2}+3\right) d x$

$=\int_{0}^{2}\left(2 x-x^{2}\right) d x$
$=\left[\frac{2 x^{2}}{2}-\frac{x^{3}}{3}\right]_{0}^{2}$
$=\left[4-\frac{8}{3}\right]=\frac{4}{3}$ sq units
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Concepts Used:

Applications of Integrals

There are distinct applications of integrals, out of which some are as follows:

In Maths

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