Question:

The approximate value of $\sqrt{6560}$ is

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When using linear approximation, choosing the closest known point (like the nearest perfect square for a square root) minimizes the error in the approximation. The smaller the $|\Delta x|$, the more accurate the result.
Updated On: Oct 17, 2025
  • 80.9939
  • 80.9838
  • 78.9939
  • 78.9838
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The Correct Option is A

Solution and Explanation

Step 1: Understanding the Concept
We can find the approximate value of a function near a known point using linear approximation (or differentials). The formula is $f(x+\Delta x) \approx f(x) + f'(x)\Delta x$. For this problem, $f(x) = \sqrt{x}$.
Step 2: Key Formula or Approach
1. Let $f(x) = \sqrt{x}$. 2. Choose a perfect square $x$ close to 6560. 3. Calculate the small change $\Delta x$ such that $x+\Delta x = 6560$. 4. Find the derivative $f'(x) = \frac{1}{2\sqrt{x}}$. 5. Apply the linear approximation formula: $\sqrt{x+\Delta x} \approx \sqrt{x} + \frac{1}{2\sqrt{x}} \Delta x$.
Step 3: Detailed Explanation
We need to approximate $\sqrt{6560}$. 1. Choose a nearby perfect square: We know that $80^2 = 6400$ and $81^2 = 6561$. The number 6561 is very close to 6560. So we choose $x=6561$. 2. Define the function and variables: Let $f(x) = \sqrt{x}$. Let $x = 6561$ and $\Delta x = 6560 - 6561 = -1$. 3. Calculate $f(x)$ and $f'(x)$ at $x=6561$: $f(6561) = \sqrt{6561} = 81$. The derivative is $f'(x) = \frac{1}{2\sqrt{x}}$. $f'(6561) = \frac{1}{2\sqrt{6561}} = \frac{1}{2 \times 81} = \frac{1}{162}$. 4. Apply the approximation formula: \[ \sqrt{6560} = f(6561 - 1) \approx f(6561) + f'(6561) \cdot (-1) \] \[ \sqrt{6560} \approx 81 - \frac{1}{162} \] Now we calculate the decimal value of $\frac{1}{162}$: \[ \frac{1}{162} \approx 0.0061728... \] So, the approximate value is: \[ \sqrt{6560} \approx 81 - 0.0061728 = 80.9938272... \] Rounding to four decimal places, we get 80.9938. Wait, my calculation gives 80.9938, which is option B. The checkmark is on option A. Let me recheck the calculation. $1/162 = 0.0061728...$ is correct. $81 - 0.00617... = 80.9938...$. The calculation is correct. The answer should be option B. The provided key marking option A seems incorrect. Let's provide the solution based on the calculation. Step 4: Final Answer
The calculated approximate value is $80.9938...$. This matches option (B). (Note: There might be an error in the provided answer key which indicates option A.)
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