The approximate value of $\sin \, 31^{\circ}$ is
- > 0.5
- > 0.6
- < 0.5
- < 0.4
The Correct Option is A
Solution and Explanation
$\ln 1^{\text {st }}$ quadrant $\sin \, x$ is increasing function
$\therefore \sin \, 31^{\circ}>\sin \, 30^{\circ}$
$\Rightarrow \sin \, 31^{\circ}>0.5$
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