Question:
The angular width of the central maximum of the diffraction pattern in a single slit of width a experiment, with $ \lambda $ as the wavelength of light, is
The angular width of the central maximum of the diffraction pattern in a single slit of width a experiment, with $ \lambda $ as the wavelength of light, is
Updated On: Jun 20, 2022
- $ \frac{3\lambda }{2a} $
- $ \frac{\lambda }{2a} $
- $ \frac{2\lambda }{a} $
- $ \frac{\lambda }{a} $
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The Correct Option is C
Solution and Explanation
The central maxima lies between the first minima on both sides.
The angular width of central maxima
$=2 \theta=\frac{2 \lambda}{a}$.
The angular width of central maxima
$=2 \theta=\frac{2 \lambda}{a}$.
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Concepts Used:
Single Slit Diffraction
In the single-slit diffraction experiment, we can examine the bending phenomenon of light or diffraction that causes light from a coherent source to hinder itself and produce an extraordinary pattern on the screen called the diffraction pattern.
Read More: Difference Between Diffraction and Interference
Central Maximum
