Question:

The angle of elevation of the sun, when shadow of a pole of 'h' metre height is \(\sqrt{3}\)h metre long is

Updated On: Apr 5, 2025
  • 60°
  • 30°
  • 45°
  • 50°
Hide Solution
collegedunia
Verified By Collegedunia

The Correct Option is B

Solution and Explanation

Correct answer: 30° 

Explanation:
Let the height of the pole be \( h \) meters and the length of the shadow be \( \sqrt{3} h \) meters. In this case, the tangent of the angle of elevation \( \theta \) is given by: \[ \tan \theta = \frac{\text{height of pole}}{\text{length of shadow}} = \frac{h}{\sqrt{3}h} = \frac{1}{\sqrt{3}} \] We know that: \[ \tan 30^\circ = \frac{1}{\sqrt{3}} \] Therefore, the angle of elevation is \( 30^\circ \).

Hence, the angle of elevation of the sun is 30°.

Was this answer helpful?
0
0