Correct answer: 30°
Explanation:
Let the height of the pole be \( h \) meters and the length of the shadow be \( \sqrt{3} h \) meters. In this case, the tangent of the angle of elevation \( \theta \) is given by: \[ \tan \theta = \frac{\text{height of pole}}{\text{length of shadow}} = \frac{h}{\sqrt{3}h} = \frac{1}{\sqrt{3}} \] We know that: \[ \tan 30^\circ = \frac{1}{\sqrt{3}} \] Therefore, the angle of elevation is \( 30^\circ \).
Hence, the angle of elevation of the sun is 30°.