Question:

The angle between velocity and acceleration of a particle describing uniform circular motion is

Updated On: May 27, 2022
  • $45 ^{\circ}$
  • $60^{\circ}$
  • $90^{\circ}$
  • $180^{\circ}$
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The Correct Option is C

Solution and Explanation

When an object follows a circular path at a constant speed, the motion of object is called uniform circular motion
Although the speed does not vary the particle is accelerating because the velocity changes its direction at every point on circular track.

The acceleration is centripetal, which is perpendicular to motion at every point and acts along the radius and directed towards the centre of the curved circular path.
$=\frac{90 \times 10^{-3}}{\frac{22}{7} \times\left(\frac{0.1 \times 10^{-3}}{2}\right)^{2}} $
$=\frac{90 \times 10^{-3}}{3.14 \times\left(\frac{0.1 \times 10^{-3}}{2}\right)^{2}} $
$= 12000 \times 10^{3}$
$= 12 \times 10^{7} \,A / m ^{2}$
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Concepts Used:

Motion in a Plane

It is a vector quantity. A vector quantity is a quantity having both magnitude and direction. Speed is a scalar quantity and it is a quantity having a magnitude only. Motion in a plane is also known as motion in two dimensions. 

Equations of Plane Motion

The equations of motion in a straight line are:

v=u+at

s=ut+½ at2

v2-u2=2as

Where,

  • v = final velocity of the particle
  • u = initial velocity of the particle
  • s = displacement of the particle
  • a = acceleration of the particle
  • t = the time interval in which the particle is in consideration