Step 1: Find the slopes of the two lines.
The equation of the first line is \( y = \sqrt{3}x - 1 \), so the slope is \( m_1 = \sqrt{3} \).
The equation of the second line is \( y = \frac{1}{\sqrt{3}}x - \frac{7}{\sqrt{3}} \), so the slope is \( m_2 = \frac{1}{\sqrt{3}} \).
Step 2: Use the formula for the angle between two lines.
The formula for the angle \( \theta \) between two lines with slopes \( m_1 \) and \( m_2 \) is:
\[
\tan \theta = \left| \frac{m_1 - m_2}{1 + m_1 m_2} \right|
\]
Substitute \( m_1 = \sqrt{3} \) and \( m_2 = \frac{1}{\sqrt{3}} \) into the formula:
\[
\tan \theta = \left| \frac{\sqrt{3} - \frac{1}{\sqrt{3}}}{1 + \sqrt{3} \cdot \frac{1}{\sqrt{3}}} \right| = \left| \frac{\frac{2\sqrt{3}}{3}}{2} \right| = \frac{1}{\sqrt{3}}
\]
Step 3: Conclusion.
Thus, the acute angle between the lines is \( 30^\circ \).