Question:

The acceleration a of moving body from rest is 2 (t - 1). Then, the velocity at 5 s will be

Updated On: Jun 21, 2022
  • 15 m/s
  • 25 m/s
  • 35 m/s
  • 45 m/s
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The Correct Option is A

Solution and Explanation

Acceleration $ a=\frac{dv}{dt}=2(t-1) $ Integrating, $ v={{t}^{2}}-2t+c $ Velocity $ v=0 $ at $ t=0 $ $ \therefore $ $ c=0 $ $ v={{t}^{2}}-2t $ $ \therefore $ Velocity at 5 s $ v={{(5)}^{2}}-2\times 5 $ $ =15m/s $
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Concepts Used:

Motion in a Plane

It is a vector quantity. A vector quantity is a quantity having both magnitude and direction. Speed is a scalar quantity and it is a quantity having a magnitude only. Motion in a plane is also known as motion in two dimensions. 

Equations of Plane Motion

The equations of motion in a straight line are:

v=u+at

s=ut+½ at2

v2-u2=2as

Where,

  • v = final velocity of the particle
  • u = initial velocity of the particle
  • s = displacement of the particle
  • a = acceleration of the particle
  • t = the time interval in which the particle is in consideration