Ten points are marked on a straight line and eleven points are marked on another straight line. How many triangles can be constructed with vertices from among the above points?
- 495
- 550
- 1045
- 2475
The Correct Option is C
Solution and Explanation
A triangle can be formed by taking any two points of a straight line and third point on the second straight line
\(\rightarrow \)Number of ways =\((C\frac{10}{2}\times 11)+(C\frac{11}{2}\times 10)\)
\(\rightarrow 495+550=1045\)
The correct answer is (C) : 1045
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In the adjoining figure, \(PQ \parallel XY \parallel BC\), \(AP=2\ \text{cm}, PX=1.5\ \text{cm}, BX=4\ \text{cm}\). If \(QY=0.75\ \text{cm}\), then \(AQ+CY =\)
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If a line drawn parallel to one side of a triangle intersecting the other two sides in distinct points divides the two sides in the same ratio, then it is parallel to the third side. State and prove the converse of the above statement.
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