Question:
\(\displaystyle\lim_{t\rightarrow0}\frac{sin(t^2)}{tsin(5t)} \ is\ equal\ to\)
\(\displaystyle\lim_{t\rightarrow0}\frac{sin(t^2)}{tsin(5t)} \ is\ equal\ to\)
Updated On: Jan 30, 2025
- 5
- 25
- \(\frac{1}{25}\)
- \(\frac{1}{5}\)
- 0
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The Correct Option is D
Solution and Explanation
The correct option is (D) : \(\frac{1}{5}\)
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