Question:
\(\lim\limits_{t\rightarrow0}\frac{\sin2t}{8t^2+4t}\) is equal to
\(\lim\limits_{t\rightarrow0}\frac{\sin2t}{8t^2+4t}\) is equal to
Updated On: Jun 10, 2024
- \(\frac{1}{2}\)
- \(\frac{2}{5}\)
- \(\frac{1}{6}\)
- \(\frac{1}{3}\)
- 1
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The Correct Option is A
Solution and Explanation
The correct option is (A): \(\frac{1}{2}\)
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