
We are given the following relationships between areas of triangles:
\(Area \ of \ △ABD : Area \ of \ △BDC = 1 : 1\)
Thus, the area of \(△ABD = 54\)
\(Area \ of \ △EDB : Area \ of \ △ADE = 1 : 1\)
Thus, the area of \(△ADE = 27\)
As a result, O is the centroid, which divides the medians in a \(2:1\) ratio.
\(Area \ of \ △BEO : Area \ of \ △EOD = 2 : 1\)
Now, the area of \(△EOD = 9\)
The area of \(△EOD\) is \(9\) square cm.
For any natural number $k$, let $a_k = 3^k$. The smallest natural number $m$ for which \[ (a_1)^1 \times (a_2)^2 \times \dots \times (a_{20})^{20} \;<\; a_{21} \times a_{22} \times \dots \times a_{20+m} \] is: