Question

sulphide are on roasting gives a gas x. x reacts with cl₂ in the presence of activated charcoal to give Y.Y is:

• A. SOCl₂
• B. SO₂Cl₂/div>
• C. S₂Cl₂
• D. SCl₆

Answer 1

The Correct Option is B

When sulphide ores (such as ZnS) are roasted in the presence of oxygen, they are converted into their corresponding metal oxides, and sulfur dioxide (SO\(_2\)) is released as a gas. This gas is represented as X in the problem. The reaction is: \[ \text{ZnS} + \text{O}_2 \rightarrow \text{ZnO} + \text{SO}_2 \quad \text{(X = SO}_2\text{)}. \] Then, when sulfur dioxide (SO\(_2\)) reacts with chlorine (Cl\(_2\)) in the presence of activated charcoal, it forms sulfuryl chloride (SO\(_2\)Cl\(_2\)): \[ \text{SO}_2 + \text{Cl}_2 \xrightarrow{\text{activated charcoal}} \text{SO}_2\text{Cl}_2. \] Thus, Y is sulfuryl chloride (SO\(_2\)Cl\(_2\)).

Therefore, the correct answer is (B): SO\(_2\)Cl\(_2\).

Answer 2

When sulphide ore (like \( \text{FeS} \)) is roasted, it produces \( \text{SO}_2 \) gas. The reaction is as follows: \[ \text{FeS} + \text{O}_2 \rightarrow \text{FeO} + \text{SO}_2 \] The \( \text{SO}_2 \) gas reacts with chlorine gas (\( Cl_2 \)) in the presence of activated charcoal (a catalyst) to form \( \text{SO}_2 \text{Cl}_2 \) (sulfuryl chloride). The reaction is: \[ \text{SO}_2 + \text{Cl}_2 \xrightarrow{\text{charcoal}} \text{SO}_2 \text{Cl}_2 \] Thus, the product Y formed is \( \text{SO}_2 \text{Cl}_2 \), which is the correct answer.