
Chlorides of Be and Al are
\(BeCl_2\) and \(AlCl_3\) have electron deficiency at central atom and behave as the Lewis acids.
\(BeCl_2 + H_2O → [Be(OH)_4]^{2-}Beryllate \;ion\)
\(AlCl_3 + H_2O → [Al(OH)_4]- aluminate \;ion\)
The correct answer is (D): Statement I is false but Statement II is true
Match List-I with List-II:
Let the shortest distance between the lines $\frac{x-3}{3} = \frac{y-\alpha}{-1} = \frac{z-3}{1}$ and $\frac{x+3}{-3} = \frac{y+7}{2} = \frac{z-\beta}{4}$ be $3\sqrt{30}$. Then the positive value of $5\alpha + \beta$ is
Uniform magnetic fields of different strengths $ B_1 $ and $ B_2 $, both normal to the plane of the paper, exist as shown in the figure. A charged particle of mass $ m $ and charge $ q $, at the interface at an instant, moves into region 2 with velocity $ v $ and returns to the interface. It continues to move into region 1 and finally reaches the interface. What is the displacement of the particle during this movement along the interface?
Consider the velocity of the particle to be normal to the magnetic field and  $ B_2 > B_1 $.
For a given reaction \( R \rightarrow P \), \( t_{1/2} \) is related to \([A_0]\) as given in the table. Given: \( \log 2 = 0.30 \). Which of the following is true? 
 
| \([A]\) (mol/L) | \(t_{1/2}\) (min) | 
|---|---|
| 0.100 | 200 | 
| 0.025 | 100 | 
A. The order of the reaction is \( \frac{1}{2} \). 
B. If \( [A_0] \) is 1 M, then \( t_{1/2} \) is \( 200/\sqrt{10} \) min. 
C. The order of the reaction changes to 1 if the concentration of reactant changes from 0.100 M to 0.500 M. 
D. \( t_{1/2} \) is 800 min for \( [A_0] = 1.6 \) M. 
In organic chemistry, an alkane, or paraffin (a historical trivial name that also has other meanings), is an acyclic saturated hydrocarbon. In other words, an alkane consists of hydrogen and carbon atoms arranged in a tree structure in which all the carbon-carbon bonds are single. Alkanes have the general chemical formula CnH2n+2. The alkanes range in complexity from the simplest case of methane (CH4), where n = 1 (sometimes called the parent molecule), to arbitrarily large and complex molecules, like pentacontane (C50H102) or 6-ethyl-2-methyl-5-(1-methylethyl) octane, an isomer of tetradecane (C14H30).
Due to very little difference of electronegativity between carbon and hydrogen and covalent nature of C-C bond or C-H bond, alkanes are generally non-polar molecules.As we generally observe, polar molecules are soluble in polar solvents whereas non-polar molecules are soluble in non-polar solvents. Hence, alkanes are hydrophobic in nature that is, alkanes are insoluble in water.
As the intermolecular Van Der Waals forces increase with the increase of the molecular size or the surface area of the molecule we observe:The straight-chain alkanes are observed to have a higher boiling point in comparison to their structural isomers.
The melting point of alkanes follow the same trend as their boiling point that is, it increases with increase in molecular weight.