Statement I: High concentration of strong nucleophilic reagent with secondary alkyl halides which do not have bulky substituents will follow \(S_N2\) mechanism.
Statement II: A secondary alkyl halide when treated with a large excess of ethanol follows \(S_N1\) mechanism.
In the light of the above statements, choose the most appropriate from the questions given below:
Analysis of Statement I: SN2 reactions are characterized by a single concerted step where the nucleophile attacks the substrate from the opposite side of the leaving group. High concentration of a strong nucleophile enhances the rate of SN2 reactions, especially with secondary alkyl halides that are not hindered by bulky substituents. Thus, Statement I is true.
Analysis of Statement II: SN1 reactions occur in two steps: formation of a carbocation intermediate followed by nucleophilic attack. Secondary alkyl halides can undergo SN1 reactions in the presence of polar protic solvents like ethanol. A large excess of ethanol serves as a nucleophile and stabilizes the carbocation, favoring the SN1 mechanism. Thus, Statement II is also true.
Therefore, both statements are correct: Both Statement I and Statement II are true.
Analyze the two given statements regarding the reaction mechanisms of secondary alkyl halides and determine their correctness and relationship.
The mechanism followed by an alkyl halide (SN1 or SN2) depends on multiple factors:
Step 1: Analyze Statement I. It states that a high concentration of a strong nucleophile with a secondary alkyl halide lacking bulky substituents will follow the SN2 mechanism. This is correct. A strong nucleophile promotes the SN2 pathway, and the absence of bulky groups reduces steric hindrance, which is a major deterrent for the SN2 mechanism, especially at a secondary carbon.
Step 2: Analyze Statement II. It states that a secondary alkyl halide treated with a large excess of ethanol follows the SN1 mechanism. Ethanol is a polar protic solvent and a weak nucleophile. These conditions favor the ionization of the alkyl halide to form a carbocation, which is the rate-determining step of the SN1 mechanism. Therefore, Statement II is also correct.
Step 3: Determine the relationship between the statements. Statement I describes conditions leading to SN2 (strong nucleophile, low steric hindrance). Statement II describes different conditions leading to SN1 (weak nucleophile/solvent, polar protic medium). Both statements are independently correct, but Statement II is not a correct explanation for Statement I, as it describes a different and opposite set of conditions.
Thus, both Statement I and Statement II are correct.
The correct IUPAC name of (CH₃)₃C-CH₂Br is:
An organic compound $[ A ]\left( C _4 H _{11} N \right)$, shows optical activity and gives $N _2$ gas on treatment with The structure of $A$ is :

In the first configuration (1) as shown in the figure, four identical charges \( q_0 \) are kept at the corners A, B, C and D of square of side length \( a \). In the second configuration (2), the same charges are shifted to mid points C, E, H, and F of the square. If \( K = \frac{1}{4\pi \epsilon_0} \), the difference between the potential energies of configuration (2) and (1) is given by:
The hydrocarbons such as Haloalkanes and Haloarenes are the ones, in which one or more hydrogen atoms are replaced with halogen atoms. The main difference between Haloalkanes and Haloarenes is that Haloalkanes are derived from open chained hydrocarbons, also called alkanes, and Haloarenes are derived from aromatic hydrocarbons.