Starting with a single cell, what will be number of cells after 'n' cycles of cell division, given that in each cycle every cell divides into two cells?
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For questions involving exponential growth due to repeated doubling, use the formula \(2^n\), where \(n\) is the number of divisions.
Step 1: Understand the cell division process Each cycle of cell division causes every cell present to divide into two daughter cells.
Step 2: Analyze how the number of cells increases Start with 1 cell.
After 1st cycle: \(2^1 = 2\) cells.
After 2nd cycle: \(2^2 = 4\) cells.
After 3rd cycle: \(2^3 = 8\) cells.
After \(n\) cycles: the total number of cells becomes \(2^n\).
Step 3: Eliminate incorrect options \(2^2\) is correct only for \(n = 2\), not general. \(n^n\) and \(n^2\) do not represent exponential growth. Therefore, only \(2^n\) correctly models exponential cell division.