Question:

Starting from the origin at time $t=0$, with initial velocity $5 \hat{ j } \,ms ^{-1},$ a particle moves in the $x - y$ plane with a constant acceleration of $(10 \hat{ i }+4 \hat{ j }) ms ^{-2} .$ At time $t$, its coordinates are (20 $\left. m , y _{0} m \right)$. The values of $t$ and $y _{0}$, are respectively

Updated On: Sep 14, 2024
  • $4 \,s$ and $52\, m$
  • $2\, s$ and $24\, m$
  • $2\, s$ and $18\, m$
  • $5\, s$ and $25\, m$
Hide Solution
collegedunia
Verified By Collegedunia

The Correct Option is C

Solution and Explanation

Given $\vec{ u }=5 \hat{ j } m / s , \vec{ a }=10 \hat{ i }+4 \hat{ j },$ final coordinate $\left(20, y_{0}\right)$ in time $t$ $S_{x}=4_{x} t+\frac{1}{2} a_{x} t^{2}$ $20-0=0+\frac{1}{2} \times 10 \times t^{2}$ $t=2 sec$ $S_{y}=u_{y} \times t+\frac{1}{2} a_{y} t^{2}$ $y _{0}=5 \times 2+\frac{1}{2} 4 \times 2^{2}=18 m$ $2 \sec$ and $18 m$
Was this answer helpful?
0
0

Concepts Used:

Acceleration

In the real world, everything is always in motion. Objects move at a variable or a constant speed. When someone steps on the accelerator or applies brakes on a car, the speed of the car increases or decreases and the direction of the car changes. In physics, these changes in velocity or directional magnitude of a moving object are represented by acceleration

acceleration