sp\(^3\) d\(^2\) hybridisation is not displayed by:
Show Hint
- BrF\(_5\)
- SF\(_6\)
- [CrF\(_6\)]\(^{3-}\)
- PF\(_5\)
The Correct Option is D
Solution and Explanation
Step 1: {Hybridisation of the Central Atom}
In sp\(^3\) d\(^2\) hybridisation, the central atom undergoes hybridisation by combining one \(s\), three \(p\), and two \(d\) orbitals, resulting in six hybrid orbitals. This hybridisation occurs in species where the central atom is bonded to six other atoms.
Step 2: {Analysis of Compounds}
In BrF\(_5\), bromine undergoes sp\(^3\) d\(^2\) hybridisation, as it is bonded to five fluorine atoms.
In SF\(_6\), sulfur undergoes sp\(^3\) d\(^2\) hybridisation, as it is bonded to six fluorine atoms.
In [CrF\(_6\)]\(^{3-}\), chromium undergoes sp\(^3\) d\(^2\) hybridisation due to the bonding with six fluoride ions.
In PF\(_5\), phosphorus undergoes sp\(^3\) hybridisation, as it is bonded to five fluorine atoms, not six.
Thus, the correct answer is (D).
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