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solve the system of equations x y 3 x y 1
Question:
Solve the system of equations: \(x + y = 3\), \(x - y = 1\).
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Use addition or subtraction to eliminate one variable in a system of linear equations.
BITSAT - 2025
BITSAT
Updated On:
Jan 13, 2026
\(x = 1, y = 2\)
\(x = 2, y = 1\)
\(x = 3, y = 0\)
\(x = 0, y = 3\)
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The Correct Option is
B
Solution and Explanation
Add the equations: \[ (x + y) + (x - y) = 3 + 1 \implies 2x = 4 \implies x = 2 \] Subtract the second from the first: \[ (x + y) - (x - y) = 3 - 1 \implies 2y = 2 \implies y = 1 \] Verify: For \(x = 2, y = 1\), \(2 + 1 = 3\) and \(2 - 1 = 1\), which satisfies both equations. Thus, option (2) is correct.
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