Step 1: Find the common denominator The denominator is $x(2x + 3)$. Rewrite: \[ \frac{4(2x + 3) - 5x}{x(2x + 3)} = 3. \] Step 2: Simplify the numerator \[ \frac{8x + 12 - 5x}{x(2x + 3)} = 3 \implies \frac{3x + 12}{x(2x + 3)} = 3. \] Step 3: Cross-multiply \[ 3x + 12 = 3x(2x + 3) \implies 3x + 12 = 6x^2 + 9x. \] Rearrange: \[ 6x^2 + 6x - 12 = 0. \] Simplify: \[ x^2 + x - 2 = 0. \] Step 4: Solve the quadratic equation Factorize: \[ x^2 + x - 2 = (x + 2)(x - 1) = 0. \] \[ x = -2 \quad \text{or} \quad x = 1. \] Step 5: Check solutions For $x = -2$, $2x + 3 = -1$, so the denominator is undefined. Therefore, $x = -2$ is not valid. Correct Answer: $x = 1$.
A shopkeeper sells an item at a 20 % discount on the marked price and still makes a 25 % profit. If the marked price is 500 rupees, what is the cost price of the item?
"जितेंद्र नार्गे जैसे गाइड के साथ किसी भी पर्यटन स्थल का भ्रमण अधिक आनंददायक और यादगार हो सकता है।" इस कथन के समर्थन में 'साना साना हाथ जोड़ि .......' पाठ के आधार पर तर्कसंगत उत्तर दीजिए।