To solve the problem, we need to find how many students play neither football nor cricket using the principle of inclusion-exclusion.
- Total students = 50
- Students playing football (F) = 30
- Students playing cricket (C) = 25
- Students playing both (F ∩ C) = 10
- Students playing football or cricket or both (F ∪ C) = F + C - (F ∩ C)
\[ |F \cup C| = 30 + 25 - 10 = 45 \]
\[ \text{Students playing neither} = \text{Total} - |F \cup C| = 50 - 45 = 5 \]
The number of students who play neither football nor cricket is 5.
A shopkeeper sells an item at a 20 % discount on the marked price and still makes a 25 % profit. If the marked price is 500 rupees, what is the cost price of the item?