Solve and check result: \(2y+\frac{5}{3}=\frac{26}{3}-y\)
\(2y+\frac{5}{3}=\frac{26}{3}-y\)
Transposing \(y\) to L.H.S and \(\frac{5}{3}\) to R.H.S, we obtain
\(2y+y=\frac{26}{3}-\frac{5}{3}\)
\(3y\) = \(\frac{21}{3}\) = \(7\)
Dividing both sides by \(3\), we obtain
\(y\) = \(\frac{7}{3}\)
L.H.S = \(2y+\frac{5}{3}\)
=\(2×\frac{7}{3}+\frac{5}{3}\)
=\(\frac{14}{3}+\frac{5}{3}\)
=\(\frac{19}{3}\)
R.H.S = \(\frac{26}{3}-y\)
=\(\frac{26}{3}-\frac{7}{3}\)
=\(\frac{19}{3}\)
L.H.S. = R.H.S.
Hence, the result obtained above is correct.
Fill in the blanks using the correct form of the verbs in brackets.
My little sister is very naughty. When she ____ (come) back from school yesterday, she had _____(tear) her dress. We _____(ask) her how it had _____(happen). She ______(say) she _____ _____ (have, quarrel) with a boy. She _____ _____ (have, beat) him in a race and he _____ ____ (have, try) to push her. She _____ ____ (have, tell) the teacher and so he _____ _____ (have, chase) her, and she _____ _____ (have, fall) down and _____ _____ (have, tear) her dress.