The given differential equation is: \[ xdy - ydx = 0 \] Rearranging terms: \[ \frac{dy}{dx} = \frac{y}{x} \] This is a separable differential equation. By separating variables: \[ \frac{dy}{y} = \frac{dx}{x} \] Integrating both sides: \[ \ln|y| = \ln|x| + C \] This implies: \[ y = Cx \]
So, the correct answer is (C) : Straight line passing through origin.
Let \( f : \mathbb{R} \to \mathbb{R} \) be a twice differentiable function such that \( f(x + y) = f(x) f(y) \) for all \( x, y \in \mathbb{R} \). If \( f'(0) = 4a \) and \( f \) satisfies \( f''(x) - 3a f'(x) - f(x) = 0 \), where \( a > 0 \), then the area of the region R = {(x, y) | 0 \(\leq\) y \(\leq\) f(ax), 0 \(\leq\) x \(\leq\) 2\ is :