Question

Simplify and solve the linear equation \(0.25(4f-3)=0.05(10f-9)\)

Answer 1

\(0.25(4f-3)=0.05(10f-9)\)

\(\frac{1}{4}(4f-3)=\frac{1}{20}(10f-9)\)

Multiplying both sides by \(20\), we obtain
\(5(4f - 3) = 10f - 9\)
\(\Rightarrow\) \(20f - 15 = 10f - 9\) (Opening the brackets)
\(\Rightarrow\) \(20f - 10f = - 9 + 15\)
\(\Rightarrow\) \(10f = 6\)
\(\Rightarrow\) \(f = \frac{3}{5}\)
\(=0.6\)