Let OA be the line joining the origin, O(0,0,0), and the point A(2,1,1).
Also, let BC be the line joining the points B(3,5,-1) and C(4,3,-1).
The direction ratios of OA are 2, 1, and 1 and of BC are (4-3)=1, (3-5)=-2, and (-1+1)=0.
OA is perpendicular to BC, if a1a2+b1b2+c1c2=0
Thus, OA is perpendicular to BC.
Let the lines $L_1 : \vec r = \hat i + 2\hat j + 3\hat k + \lambda(2\hat i + 3\hat j + 4\hat k)$, $\lambda \in \mathbb{R}$ and $L_2 : \vec r = (4\hat i + \hat j) + \mu(5\hat i + + 2\hat j + \hat k)$, $\mu \in \mathbb{R}$ intersect at the point $R$. Let $P$ and $Q$ be the points lying on lines $L_1$ and $L_2$, respectively, such that $|PR|=\sqrt{29}$ and $|PQ|=\sqrt{\frac{47}{3}}$. If the point $P$ lies in the first octant, then $27(QR)^2$ is equal to}

