Let us consider that ABC is an equilateral triangle.
Therefore, AB = BC = AC AB = AC
∠C =∠ B (Angles opposite to equal sides of a triangle are equal)
Also,
Ac = BC
∠B = ∠A (Angles opposite to equal sides of a triangle are equal)
Therefore, we obtain A
= ∠B = ∠C
In ∆ABC,
∠A + ∠B + C = 180°
∠A + ∠A +∠A = 180°
∠3A = 180°
∠A = 60°
∠A = ∠B = ∠C = 60°
Hence, in an equilateral triangle, all interior angles are of measure 60º.
A driver of a car travelling at \(52\) \(km \;h^{–1}\) applies the brakes Shade the area on the graph that represents the distance travelled by the car during the period.
Which part of the graph represents uniform motion of the car?
In Fig. 9.26, A, B, C and D are four points on a circle. AC and BD intersect at a point E such that ∠ BEC = 130° and ∠ ECD = 20°. Find ∠ BAC.