
Let us consider that ABC is an equilateral triangle.
Therefore, AB = BC = AC AB = AC
∠C =∠ B (Angles opposite to equal sides of a triangle are equal)
Also,
Ac = BC
∠B = ∠A (Angles opposite to equal sides of a triangle are equal)
Therefore, we obtain A
= ∠B = ∠C
In ∆ABC,
∠A + ∠B + C = 180°
∠A + ∠A +∠A = 180°
∠3A = 180°
∠A = 60°
∠A = ∠B = ∠C = 60°
Hence, in an equilateral triangle, all interior angles are of measure 60º.
(i) The kind of person the doctor is (money, possessions)
(ii) The kind of person he wants to be (appearance, ambition)
ABCD is a quadrilateral in which AD = BC and ∠ DAB = ∠ CBA (see Fig. 7.17). Prove that
(i) ∆ ABD ≅ ∆ BAC
(ii) BD = AC
(iii) ∠ ABD = ∠ BAC.
