Question

\( \sec^2 23^\circ - \tan^2 23^\circ + 2 \) is:

• A. \( 0 \)
• B. \( 1 \)
• C. \( 2 \)
• D. \( 3 \)

Hint:

The identity: \[ \sec^2 \theta - \tan^2 \theta = 1 \] is useful for solving such problems.

Answer 1

The Correct Option is C

Using the trigonometric identity:
\[ \sec^2 \theta - \tan^2 \theta = 1 \] Substituting \( \theta = 23^\circ \):
\[ 1 + 2 = 2 \]