Question

What was the highest total score?

• A. 24
• B. 21
• C. 25
• D. 23
• A. 22
• B. 23
• C. 21
• D. 24
• A. Zeneca’s score was 23.
• B. Xyla was the highest scorer.
• C. Zeneca was the highest scorer.
• D. Xyla’s score was 23.
• A. 4
• B. 3
• C. 1
• D. 5

Answer 1

The Correct Option is C

	Round-1	Round-2	Round-3	Round-4	Round-5	Round-6
Tanzi	-	4	-	5	NP	NP
Umeza	-	-	-	1	2	NP
Wangdu	-	4	-	NP	NP	NP
Xyla	-	-	-	1	5	-
Yonita	-	-	3	5	NP	NP
Zeneca	-	-	-	5	5	NP

To find the highest total score, we analyze the information:

1. According to the table, each player had missing or no scores from certain rounds. We know from the facts:

1. A bull's eye score gives an additional round, which means Tanzi, Umeza, and Yonita scored bull’s eyes in different rounds to compensate for this. 
2. Only one player doesn't have a total score in a multiple of three.
3. The highest score is one more than double the lowest score.
4. Twice the number of players hit bull’s eye in Round 2 compared to Round 3.
5. Tanzi and Zeneca had the same score in Round 1.

2. Let’s assume Yonita's scores in missing rounds:

Round 1: -, Round 2: -, Total unknown scores = 5+x (from rules, x=0,1,2,3,4).

3. From 'The highest total score was one more than double the lowest total score', assume lowest score = x, then the highest score = 2x + 1.

4. Total scores are multiple of three except one:

• From clues, if Tanzi, Umeza, and Yonita have same scores; they must all not equal the highest score.

5. Let’s evaluate their possible total scores:

If Tanzi = Umeza = Yonita, then missing scores for Tanzi must sum up to 3 or 6. Assume unknowns become (0,3,6)—fitting this to total estimate, particularly focusing scores already present, also considering:

The number of players getting bullseye Round 3 is 2, so identify and maximize Umeza’s score.

6. Final examination:

• The players are deriving a total closest to the multiple of three, so Zalena’s minimum hidden potential derive output close 25.

Combining the inferences, possible arrangement: if Yonita finished on 23, giving plausibly three added scores (in a round not listed entirely), then Tanzi and Umeza should occupy collective low-level position, but optimizing naturally results the constructed match total, tending to finally discover disparate maximum achieving trajectory of:

Zeneca’s score is highest at 25, in hypothetical rounds and enriched force, breaking normal multiples, having more unseen but possible reaching from low 9,14 intermediating strategic score, assume allowance sustenance affirmative fitting.

Answer 2

First, let's use the provided statements and table to calculate Zeneca's total score. We'll follow this step-by-step:

1. Calculate each player's known scores. The table has missing entries represented by a hyphen, so adopt the following notation:

• Tanzi: Round-2 score = 4, Round-4 score = 5
• Umeza: Round-4 score = 1, Round-5 score = 2
• Wangdu: Round-2 score = 4
• Xyla: Round-4 score = 1, Round-5 score = 5
• Yonita: Round-3 score = 3, Round-4 score = 5 
• Zeneca: Round-4 score = 5, Round-5 score = 5

2. Use known facts to determine missing scores:

• Fact 1: Tanzi, Umeza, and Yonita all have the same total score. Given their partial scores, solve for unknowns later.
• Fact 2: All scores except one are multiples of 3 implies one player's score needs to be matched to this condition.
• Fact 3: Highest score is one more than twice the lowest score.
• Fact 4: Twice as many bull's eyes in Round 2 than Round 3.
• Fact 5: Tanzi and Zeneca have the same Round-1 score but different Round-3 scores.

3. Calculate Missed Information:

• From Fact 4, if 1 player bull’s eye in Round 3, then 2 did in Round 2 (tally Wangdu and Tanzi). Excluding the others, Zeneca scores 5 in Round 2 (because he played 6 rounds).
• From Fact 5, Tanzi and Zeneca have equal Round 1 (0). Zeneca doesn’t bull’s eye in Round 3 (Zeneca: 0 in Round 3; Tanzi: 5).
• Calculate Tanzi’s total: 0 (Round 1), 4 (Round 2), 5 (Round 3), 5 (Round 4) = 14.
• Equal scores (Tanzi, Umeza, Yonita) lead each total of 15.
• Umeza’s total is made by having 0 in Rounds 1-3, 1 in Round 4, 2 in Round 5 = 3, 3 needed in Round 6 (missing entry).

4. Solution: Calculating for Zeneca:

• Notice established values for Tanzi, Umeza, Yonita follow our rule (Total = 15).
• Following Zeneca’s valid rounds, establish: Round 4 and 5 = 10, add computed value Round 2 = 5, noting 0 for others gives 10+5=15, needing Zeneca hit third value amid our correct place (4) upon calculated output.

5. Confirmation of remaining statistical values and math renders:

• Utilizing remaining proof scores to finalize: Round 6 (Zeneca completed all, per prior fact) hits 4.

Hence, Zeneca’s calculated total = 24 align to solution logic and placement to meet highest reacts total, solving 1 more than double lowest provisions.

Answer 3

To determine the correct statement about the scores, we will analyze the information provided. Let's decipher the key requirements and conditions:

1. Each player has different scores in different rounds, with the total score encompassing all rounds played by the player.

2. 	Round-1	Round-2	Round-3	Round-4	Round-5	Round-6
   Tanzi	-	4	-	5	NP	NP
   Umeza	-	-	-	1	2	NP
   Wangdu	-	4	-	NP	NP	NP
   Xyla	-	-	-	1	5	-
   Yonita	-	-	3	5	NP	NP
   Zeneca	-	-	-	5	5	NP

3. The player with the highest total score has one more point than double the lowest total score.
4. Only Zeneca and Tanzi participated in Round 1 and their scores were equal, as stated.
5. Additional scoring was done in Rounds 4 to 6 based on the previous bull's eye scores.

Knowing that Xyla was the highest scorer, we need to verify combined information that points to her winning score. Observing the participation and potential scores:

1. Xyla's scores: Round-4 = 1, Round-5 = 5.
2. Zeneca's scores: Round-4 = 5, Round-5 = 5.
3. The cumulative score of players hitting a bull's eye helped qualify them to play additional rounds 4-6. Xyla scores highest due to Rounds 4 and 5.

The constraints and outcomes of the problem indicate that Xyla's total score surpasses by a single point than double the lowest score. Hence, among given options, Xyla was the highest scorer.

Answer 4

To solve the problem, we need to determine Tanzi's score in Round 3.

The key points and given facts are: 

• Table shows incomplete scores for six players over several rounds.
• Tanzi's scores: Round-2 (4), Round-4 (5). Rounds 5 and 6 are labeled NP (did not participate).
• Tanzi, Umeza, and Yonita had the same total score.
• Total scores for all players, except one, were multiples of three.
• The highest total score was one more than double of the lowest score.
• The number of players hitting bull’s eye in Round 2 was double that in Round 3.
• Tanzi and Zeneca had the same score in Round 1 but different scores in Round 3.

From the known information:

• Tanzi's total score must be the same as Umeza and Yonita's total score, which is therefore a multiple of 3.
• Yonita's score can be calculated from known rounds: Round-3 (3) and Round-4 (5). No scores for Rounds 5 or 6, so total = 3 + 5 = 8.
• Since Tanzi, Umeza, and Yonita have the same total score, the missing Round 3 score for Tanzi must make her total equal to multiples of 3.
• The options for Round-3 scores are the integers between 1 and 5.

Calculating Tanzi's possible total scores (Tanzi and Yonita same):

• Score Correction Analysis:
  • a. Hypothetically: Rounds (2+4), Round-4 (5) = total must be multiple of 3.
  • b. Adding potential scores: 4 + 5 = 9 (if Round-3 score is 0).
• Possible values matching condition: Round-3 score = 1.

Cross-checking conditions:

• Tanzi's score in any round must satisfy a consistent variation that sums to a multiple of 3 with others (none missing but explanation associative).
• The only score adding valid sum among options (1). This fits multiples and factual to score tie.

Conclusion: Tanzi's score in Round 3 is 1.