Recently my brother and I played chess form chocolates. Who ever lost the game gave the other a chocolate. After the last game we counted the chocolates. I had 20 more chocolates than I started with, although he won 7 games. There is no draw. How many games did we play?
Let the number of games that I won be \( x \). Since my brother won 7 games, the number of games he won is \( 7 \).
Given: I had 20 more chocolates than I started with. This means I won 20 more chocolates than I lost. Therefore, the net chocolates I have can be expressed as:
\( x - 7 = 20 \)
Simplifying:
\( x = 27 \)
This indicates I won 27 games.
The total number of games played is the sum of games I won and the games my brother won:
\( x + 7 = 27 + 7 = 34 \)
Therefore, the total number of games played is 34.