Step 1: Understanding the Formation of P
The oxidation of iso-propylbenzene (cumene) in the presence of \( O_2 \) and acidic hydrolysis leads to the formation of phenol and acetone (P).
Step 2: Formation of Q
Reaction of P (acetone) with three equivalents of chlorine (\( Cl_2 \)) leads to the formation of trichloroacetone (Q).
Step 3: Formation of R and S
Treatment of Q with \( Ca(OH)_2 \) results in hydrolysis to form:
Step 4: Verifying the Statements
Conclusion:
The statements have been analyzed, and the correct ones are identified.
To solve the problem, we need to analyze the reaction sequence starting from iso-propylbenzene and verify the statements about compounds P, Q, R, and S.
1. Reaction of iso-propylbenzene with O2 and H3O+:
Iso-propylbenzene undergoes oxidation to form phenol and a by-product P (which is likely trichloromethylphenol or related compound).
2. Reaction of P with 3 equivalents of Cl2 to give Q:
P reacts with chlorine to form compound Q containing trichloromethyl groups (CCl3).
3. Treatment of Q with Ca(OH)2 produces R and calcium salt S:
This reaction yields compound R, which has chloroform-like structure, and S, the calcium salt of a carboxylic acid.
4. Verifying the given statements:
(A) Reaction of P with R in the presence of KOH followed by acidification gives the compound shown with a CCl3 and hydroxyl groups:
This is correct as it corresponds to the haloform reaction forming trichloromethyl derivatives.
(B) Reaction of R with O2 in presence of light gives phosgene gas (COCl2):
This is correct because R contains chloroform-like structure that can yield phosgene under these conditions.
(C) Q reacts with aqueous NaOH to produce Cl3CCH2OH and Cl3CCOO-Na+:
This is incorrect as Q is expected to form other products, not the ones stated.
(D) Heating S gives back P:
This is correct as the calcium salt S decomposes upon heating to give P.
Final Answer:
Statements (A), (B), and (D) are correct.
The order of acidity of the following compounds is:
(i) o-Nitrophenol
(ii) Phenol
(iii) o-Cresol
(iv) Ethanol
Given below are two statements:
Statement I: Dimethyl ether is completely soluble in water. However, diethyl ether is soluble in water to a very small extent.
Statement II: Sodium metal can be used to dry diethyl ether and not ethyl alcohol.
In the light of the given statements, choose the correct answer from the options given below:
List I | List II | ||
(P) | ![]() | (1) | ![]() |
(Q) | ![]() | (2) | ![]() |
(R) | ![]() | (3) | ![]() |
(S) | ![]() | (4) | ![]() |
(5) | ![]() |